给需要排序每个元素设置一个线程 然后在线程里加上sleep(当前元素) 来进行排序！ 快捷又高效🤓 

import threading
import time
 
 
def sleep_sort(numbers):
    def sleep_and_print(number):
        time.sleep(number)
        print(number)
 
    for number in numbers:
        # 创建一个新线程，让其在number秒后输出
        thread = threading.Thread(target=sleep_and_print, args=[number])
        thread.start()
 
 
numbers = [3,6,7,1,5,4,2]

显而易见 时间复杂度为O(max(num...